The ant Myrmecia pilosula is found in Australia and is named bulldog because of its aggressive...

The ant Myrmecia pilosula is found in Australia and is named bulldog because of its aggressive behavior. It is particularly interesting because it carries all its information in a single pair of chromosomes. In other words, 2n = 2. Assume that a G1 somatic cell nucleus in an ant (Myrmecia pilosula) contains 4 picograms of DNA. How much DNA would be expected in a metaphase I cell of the ant Myrmecia pilosula (2n=2 )?

a. 2 picograms

b. 4 picograms

c. 8 picograms

d. 16 picograms

Expert Solution

Here, the correct answer is 8 picograms.

Explanation -

The cell division is the process in which first of all cell prepares itself for cell division then division takes place. The cell cycle is divided into following phases : G1 , S, G2 and M phase.

During G1 phase the cell performs it's metabolic functions. During S phase the DNA duplication takes place. During G2 phase all other machinery needed are assembled and during M phase actual divisions takes place.

Thus here 2n = 2 that means the diploid somatic cell has 2 chromosomes weighing 4 picograms.

During S phase the amount of DNA will be doubled. So, during the Metaphase of the M phase the cell contains double the amount of chromatids.

Thus, it will weighs 8 picograms in weight.

gladiator answered 2 years ago

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