In: Chemistry
A solution is prepared by dissolving 17.0 g of KOH in enough water to make 80.0 mL of solution. What is the molarity of this solution?
Data given: Wegiht of KOH = 17 grams
Volume of solution = 80 ml = 80*10-3 Litre
Molar mass of KOH= 56 grams/moles
Molarity if given by ,
Molarity = number of gram moles / Volume of solution ( in Litre)
Let us now calculate number of moles,
Moles of KOH = Weight of KOH =17/56 = 0.30357 moles
Substituting all the known values in molarity equation
Molarity (M) = 0.30357 / (80*10-3) = 3.7946 M
Hence, Molarity of 80 ml KOH solution is 3.7946 M