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In: Chemistry

Determine the pH of a KOH solution made by mixing 0.251 g KOH with enough water...

Determine the pH of a KOH solution made by mixing 0.251 g KOH with enough water to make 1.00

Expert Solution

Molar mass of KOH = 56 gm

mass of KOH = 0.251 g

Number of moles of KOH = mass/molar mass

= 0.251/56

=4.482*10^-3 mol

Volume = 1*10^2 mL =0.1 L

Molarity of KOH = number of moles/ Volume

= (4.482*10^-3)/0.1

=0.04482 M

KOH-->K+ +OH-

[OH-] = [KOH]= 0.04482 M

pOH = - log[OH-]

= -log (0.04482)

= 1.35

pH= 14- pOH

= 14- 1.35

= 12.65

Answer: e

queen_honey_blossom answered 5 months ago

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