Question

When heated, ammonium carbonate decomposes as follows: NH4CO2NH2(s) ⇌ 2NH3(g) + CO2(g). At a certain temperature the equilibrium constant is K_P = 2.9 x 10^-3. Calculate the total equilibrium pressure at this temperature.

Answer 1

ans)      as NH4 CO2NH2 is solid ,Kp includes the active mass of NH4CO2NH2.

                       Kp =   P²_{NH3 *}    P CO₂

            2.9 * 10^-3      =      ( 2X)² * X

                  X³ = 2.9 * 10^-3   /4   = 0.75 * 10^-3

      BY SOLVING     x =      0.025 atm

                 P_{TOTAL   EQM}     = 2 P_{NH3 + P CO2}

                                                      = 2* 0.025 + 0.025

                                =     0.075 atm

             thank u