In: Statistics and Probability
one way to measure whether the trees in the Wade tract are uniformly distributed issue examine the average location in the north south or the Southwest direction. the values range from 0 to 200 so if the trees are uniformly distributed the average location should be 100 and any differences in the actual sample would be due to random chance. the actual sample mean in the north-south direction for the 584 trees in the tract is 99.74. a theoretical calculation for uniform distributions gives a standard deviation of 58. carefully State the null and alternative hypothesis in terms of the true average north south location. test your hypothesis by reporting your results along with the short summary of your conclusions.
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Answer:
:
The null hypothesis is :
The alternative hypothesis is :
Level of significance is 0.05
z=xbar-u/SD/sqrt(n)
=(99.74-100)/(58/sqrt(584))
z=-0.1083
p value when calculated in excel is
2*(=NORMSDIST(-0.1083))
2*(0.456878861)
p=0.9137
Conclusion
p=0.9137
alpha=.05
p value is greater than 0.05
= > We fail to reject Ho.
Accept Ho.
There is sufficient statistical evidence at 5% level of significance to conclude that trees in Wade tract are uniformly distributed