Question

What is the molarity of a solution created with 31.5 g of C6H12O6dissolved in 482 g of water to make 555 mL of solution?

Answer 1

Answer:

The molarity of a solution created with 31.5 g of C₆H₁₂O₆ dissolved in 482 g of water to make 555 mL of solution = 0.32 M

Explanation: Given: 1. Mass of C₆H₁₂O₆ = 31.5 g

2. Mass of water = 482g

3. Total volume of solution = 555 mL = 0.555 L

Now, molarity = moles/volume in liter

Here the molarity of solution is the number of moles of glucose present in total volume of solution in liter.

Now, molar mass of glucose = 180.156 g/mol

moles of glucose = mass / molar mass

= 31.5 g/ 180.156 g/mol

= 0.1748 moles

Hence, molarity of solution = moles of glucose/total volume of solution in liter

=  0.1748 moles / 0.555 L

= 0.3149 M

= 0.32 M