In: Statistics and Probability
An automobile manufacturer claims that their van has a 45.9 miles/gallon (MPG) rating. An independent testing firm has been contracted to test the MPG for this van. After testing 11 vans they found a mean MPG of 45.7 with a variance of 2.89. Is there sufficient evidence at the 0.025 level that the vans underperform the manufacturer's MPG rating? Assume the population distribution is approximately normal.
Step 1 of 5: State the null and alternative hypotheses.
Step 2 of 5: Find the value of the test statistic. Round your answer to three decimal places.
Step 3 of 5: Specify if the test is one-tailed or two-tailed.
Step 4 of 5: Determine the decision rule for rejecting the null hypothesis. Round your answer to three decimal places
Step 5 of 5: Make the decision to reject or fail to reject the null hypothesis.
Solution :
Given that ,
= 45.9
= 45.7
n = 11
2 = 2.89
= 2.89 = 1.7
1.The null and alternative hypothesis is ,
H0 : = 45.9
Ha : < 45.9
2. This is the left tailed test .
Test statistic = z
= ( - ) / / n
= ( 45.7 - 45.9 ) / 1.7 / 11
= -0.39
3. The test statistic = -0.39
= 0.025
Z = Z0.025 = -1.960
4. Reject Ho if Z < -1.960
The critical value = -1.960
-0.390 > -1.960
Test statistic > Critical value
5. Fail to reject the null hypothesis.