In: Statistics and Probability
An automobile manufacturer claims that their jeep has a 34.7 miles/gallon (MPG) rating. An independent testing firm has been contracted to test the MPG for this jeep. After testing 250 jeeps they found a mean MPG of 35.0. Assume the standard deviation is known to be 1.6. Is there sufficient evidence at the 0.02 level that the jeeps have an incorrect manufacturer's MPG rating?
Step 4 of 5: Enter the decision rule.
Ho : µ = 34.7
Ha : µ ╪ 34.7
(Two tail test)
Level of Significance , α =
0.020
population std dev , σ =
1.6000
Sample Size , n = 250
Sample Mean, x̅ = 35.0000
' ' '
Standard Error , SE = σ/√n = 1.6000 / √
250 = 0.1012
Z-test statistic= (x̅ - µ )/SE = ( 35.000
- 34.7 ) / 0.1012
= 2.965
p-Value = 0.0030 [ Excel
formula =NORMSDIST(z) ]
Decision: p-value<α, Reject null
hypothesis
conclusion: there is sufficient
evidence at the 0.02 level that the jeeps have an incorrect
manufacturer's MPG rating