Question

In: Chemistry

A voltaic cell consists of a Mn/Mn2+ electrode (E° = –1.18 V) and a Zr/Zr4+ electrode...

A voltaic cell consists of a Mn/Mn2+ electrode (E° = –1.18 V) and a Zr/Zr4+ electrode (E° = –1.53 V). Calculate [Mn2+] if [Zr4+ ] = 1.0x10−4 M and Ecell = 0.40 V at 25°C.

(1) 0.49 M           (2) 0.24 M           (3) 0.040 M         (4) 1.8 M            (5) 2.0 M

Solutions

Expert Solution

           Zr(s) -------------------> Zr^4+ (aq) + 4e^-                   E0 = 1.53v

          2Mn^2+(aq) + 4e^- -----------> 2Mn(s)                        E0 = -1.18v

--------------------------------------------------------------------------------------------------

        Zr(s) + 2Mn^2+(aq) ----------------> Zr^4+(aq) + 2Mn(s)     E0 cell = 0.35v

                      n = 4

                 Ecell   = E0 cell - 0.0591/n logQ

                  0.4     = 0.35 - 0.0591/4 log[Zr^4+]/[Mn^2+]^2

                   0.4-0.35    = -0.0591/4 log[Zr^4+]/[Mn^2+]^2

                   0.05           = -0.0147 log[Zr^4+]/[Mn^2+]^2

                  -0.05/0.0147      = log[Zr^4+]/[Mn^2+]^2

                  -3.4                  = log[Zr^4+]/[Mn^2+]^2

                  [Zr^4+]/[Mn^2+]^2    = 10^-3.4

                 [Zr^4+]/[Mn^2+]^2     = 0.000398

                 [Mn^2+]^2                 = 1*10^-4/0.000398

                 [Mn^2+]^2                = 0.25

                  [Mn^2+]                  = 0.5M   >>>>>>answer

1. 0.49M >>>>answer

               [Mn^2+]^2                     = 4*10^-8

               [Mn^2+]                         = 2*10^-8 M

               

               

               

                   

                


Related Solutions

Consider the voltaic cell composed of a Mn/Mn2+ electrode and a Fe/Fe2+ electrode. Calculate the concentration...
Consider the voltaic cell composed of a Mn/Mn2+ electrode and a Fe/Fe2+ electrode. Calculate the concentration of Fe2+ if the concentration of Mn2+ is 0.010 M and Ecell is 0.78V.
A galvanic (voltaic) cell consists of an electrode composed of nickel in a 1.0 M nickel(II)...
A galvanic (voltaic) cell consists of an electrode composed of nickel in a 1.0 M nickel(II) ion solution and another electrode composed of gold in a 1.0 M gold(III) ion solution, connected by a salt bridge. Calculate the standard potential for this cell at 25 °C. ____V 2)Consider these two entries from a fictional table of standard reduction potentials. X2+ + 2e- => X(s) E=2.26 V Y2+ + 2e- => Y(s) E=0.14 V Which pair of species would react under...
A voltaic cell employs the following redox reaction: Sn2+(aq)+Mn(s)→Sn(s)+Mn2+(aq) Calculate the cell potential at 25 ∘C...
A voltaic cell employs the following redox reaction: Sn2+(aq)+Mn(s)→Sn(s)+Mn2+(aq) Calculate the cell potential at 25 ∘C under each of the following conditions. A) Standard condition B) [Sn2+]= 1.64×10−2 M ; [Mn2+]= 2.25 M C) [Sn2+]= 2.25 M ; [Mn2+]= 1.64×10−2 M
A voltaic cell based on the reaction below has an E°cell of +0.30 V. 2Cr(s) +...
A voltaic cell based on the reaction below has an E°cell of +0.30 V. 2Cr(s) + 3Fe2+(aq) à 2Cr3+(aq) + 3Fe(s) What is the Ecell at 264 K when [Cr3+] = 1.41 x 10-2 and [Fe2+] = 1.26 x 10-2 What is ΔG under these conditions? ΔG° = -135 kJ  
A galvanic cell consists of a standard hydrogen electrode and a copper electrode. Suppose that the...
A galvanic cell consists of a standard hydrogen electrode and a copper electrode. Suppose that the copper electrode is immersed in a solution that is 0.1 M NaOH and that it is saturated with Cu(OH)2. Find the cell potential?
If the cell potential for a voltaic cell is 0.250 V, and the reduction potential for...
If the cell potential for a voltaic cell is 0.250 V, and the reduction potential for the oxidation reaction is ⎯0.150 V, what is the reduction potential for the reaction occurring at the cathode?
A student makes a voltaic cell with a Ag electrode in 1.0 M AgNO3 solution and...
A student makes a voltaic cell with a Ag electrode in 1.0 M AgNO3 solution and a Pb electrode in a 1.0 M Pb(NO3)2 solution. a. Identify the cathode and write the half reaction. b. Identify the anode and write the half reaction. c. Write the overall reaction and calculate Eocell for the voltaic cell. d. What is Ecell if the concentrations of the ions in solution are [Ag+] = 0.045 M and [Pb2+] = 0.36 M? Temperature = 298.15...
A voltaic cell is constructed using a Sn electrode in .50 M SnSO4 and a Cd...
A voltaic cell is constructed using a Sn electrode in .50 M SnSO4 and a Cd electrode in .01M CdSO4 solution. Determine the following: a) Overall reaction b) Metal oxidized c) Metal Reduced d) E0 cell e) E cell
Calculate E∘cell for each of the following balanced redox reactions. Are the reactions spontanous? A) 2Cu(s)+Mn2+(aq)→2Cu+(aq)+Mn(s)...
Calculate E∘cell for each of the following balanced redox reactions. Are the reactions spontanous? A) 2Cu(s)+Mn2+(aq)→2Cu+(aq)+Mn(s) B) MnO2(s)+4H+(aq)+Zn(s)→Mn2+(aq)+2H2O(l)+Zn2+(aq) C) Cl2(g)+2F−(aq)→F2(g)+2Cl−(aq)
A voltaic cell consists of a Pb/Pb2+ half cell and a Cu/Cu2+ half cell at 25C....
A voltaic cell consists of a Pb/Pb2+ half cell and a Cu/Cu2+ half cell at 25C. The initial concentrations of Pb2+ and Cu2+ are 0.0520 M and 0.150 M respectively. Part A: What is the initial cell potential *Write answer using two significant figures Part B: What is the cell potential when the concentration of Cu2+ has fallen to 0.210 M *Write answer using three significant figures Part C: What is the concentration of Pb2+ when the cell potential falls...
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT