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4. In fruit flies, normal eyes (+) are dominant over small eyes (ey) and straight wings...

4. In fruit flies, normal eyes (+) are dominant over small eyes (ey) and straight wings (+) are dominant over curly wings (Cy). Work the following crosses through the F2 generation, and determine the genotypic and phenotypic ratios for each generation. Assume P1 individuals are homozygous: a. +, + x ey, Cy b. +, Cy x ey, + c. +, + x +, Cy

Solutions

Expert Solution

ey+ = Normal eyes
ey- = Small eyes

Straight wings = cy+
Curly wings = cy-

a. Parental cross: ey+/ey+ cy+/cy+ X ey-/ey- cy-/cy-
F1 progeny: ey+/ey- cy+/cy-
F1 phenotype = Normal eyes and straight wings
F1 selfing: ey+/ey- cy+/cy- X ey+/ey- cy+/cy-
F2 progeny:
Genotypic ratio = 1:1:1:1:2:2:2:2:4
Phenotypic ratio = 9:3:3:1
9/16 = ey+/_ cy+/_ = Normal eyes and straight wings
3/16 = ey+/_ cy-/cy- = Normal eyes and curly wings
3/16 = ey-/ey- cy+/_ = Small eyes and straight wings
1/16 = ey-/ey- cy-/cy- = Small eyes and curly wings

b. Parental cross: ey+/ey+ cy-/cy- X ey-/ey- cy+/cy+
F1 progeny: ey+/ey- cy+/cy-
F1 phenotype = Normal eyes and straight wings
F1 selfing: ey+/ey- cy+/cy- X ey+/ey- cy+/cy-
F2 progeny:
Genotypic ratio = 1:1:1:1:2:2:2:2:4
Phenotypic ratio = 9:3:3:1
9/16 = ey+/_ cy+/_ = Normal eyes and straight wings
3/16 = ey+/_ cy-/cy- = Normal eyes and curly wings
3/16 = ey-/ey- cy+/_ = Small eyes and straight wings
1/16 = ey-/ey- cy-/cy- = Small eyes and curly wings

c. Parental cross: ey+/ey+ cy-/cy- X ey+/ey+ cy-/cy-
F1 progeny: ey+/ey+ cy+/cy-
F1 phenotype = Normal eyes and straight wings
F1 selfing: ey+/ey+ cy+/cy- X ey+/ey+ cy+/cy-
F2 progeny:
Genotypic ratio = 1:2:1
Phenotypic ratio = 3:1
3/4 = ey+/ey+ cy+/_ = Normal eyes and straight wings
1/4 = ey+/ey+ cy+/_ = Normal eyes and curly wings

gladiator answered 1 year ago
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