In: Chemistry
Dissociation of phosphorus pentachloride \(\left(P C I_{5}\right)\) is favored by-
(i)High T, High P
(ii) High T, low P
(iii) Low T, Low P
(iv) Low \(T\), High P
Phosphorus pentachloride dissociated as, \(\mathrm{PCl}_{5}(\mathrm{~g})-\mathrm{m} \mathrm{PCl}_{3}(\mathrm{~g})+\mathrm{Cl}_{2}(\mathrm{~g})\)
Now, for this reaction difference between
the gaseous products in both side, \(\Delta n=(2-1)=1\)
So, we can say that the dissociation could be
favoured by low pressure.
And in high temperature the dissociation
would be more favorable as the value of
\(\Delta \mathrm{n}=1\) for the given process.
Hence, the correct answer is "High T, low P"
The correct answer is (ii) High T , Low P