Question

A survey taken several years ago found that the average time a person spent reading the local newspaper was 10.8 minutes. The standard deviation of the population was 3 minutes. To see whether the average time had changed since the newspaper’s format had changed, the editor surveyed 36 individuals. The average time that these 36 people spent reading the newspaper was 11.2 minutes. At  = 0.05 , is the average time an individual spends reading the newspaper still 10.8?

State:__________________________________

CV: use table E, F, G, CV=___________________

TV: z, t, or 2  (circle one), TV=________________

Decide:________________________________

Summary: (remember to circle the correct description before completing the statement) There is/is not enough evidence to reject/support the claim that______________________ ________________________________________________________________________ _______________________________________________________________________

Confidence Interval:_________________________________________________ Do the results agree?__________ Explain: _____________________________________ _______________________________________________________________________

Answer 1

'There is enough evidence to support the claim that the average time a person spent reading the local newspaper was 10.8 minutes.

Since the confidence interval includes 10.8, so at 95% confidence level, we can conclude that average time an individual spends reading the newspaper still 10.8.

Yes, both results agree.