In: Math
For the following exercises, refer to Figure 15. Each square represents one square unit. For each value of a, determine which of the three conditions of continuity are satisfied at x = a and which are not.
x = 2
A function f (x) is continuous at x = a, only if it satisfies all the three following conditions:
• Condition 1: f (a) exists.
• Condition 2: limx→af(x) exists
• Condition 3: limx→af(x) = f(a)
Consider the graph provided in the exercise:
From the graph, it is clear that:
f(a) = f(2)
Since f(2) does not exist, condition 1 is not satisfied.
From the graph, it is clear that:
limx→2-f(x) = -1
limx→2+f(x) = -1
Since limx→2-f(x) = limx→2+f(x)
So, limx→2f(x) exists, condition 2 is satisfied.
Since, f(2) does not exist
So, limx→2f(x) ≠ f(2), condition 3 is not satisfied.
So, limx→2f(x) ≠ f(2), condition 3 is not satisfied.