In: Statistics and Probability
Ho : p = 0.11
H1 : p ╪ 0.11 (Two tail
test)
Level of Significance, α =
0.02
Sample Size, n = 500
Sample Proportion , p̂ = 0.70
Standard Error , SE = √( p(1-p)/n ) =
0.0140
Z Test Statistic = ( p̂-p)/SE =
(0.7-0.11)/0.014= 42.16
p-Value = 0.0000 [excel formula
=2*NORMSDIST(z)]
Decision: p-value<α , reject null
hypothesis
There is enough evidence to suggest the percentage of
children in the us who live with a grandparent is different from
11%
....................
Please let me know in case of any doubt.
Thanks in advance!
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