In: Statistics and Probability
Ho :   p =    0.11  
H1 :   p ╪   0.11   (Two tail
test)
          
Level of Significance,   α =   
0.02  
Sample Size,   n =    500  
          
Sample Proportion ,    p̂ = 0.70
          
Standard Error ,    SE = √( p(1-p)/n ) =   
0.0140  
Z Test Statistic = ( p̂-p)/SE =   
(0.7-0.11)/0.014=   42.16  
          
p-Value   =   0.0000   [excel formula
=2*NORMSDIST(z)]
Decision:   p-value<α , reject null
hypothesis
      
There is enough evidence to  suggest the percentage of
children in the us who live with a grandparent is different from
11%       
....................
Please let me know in case of any doubt.
Thanks in advance!
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