In: Statistics and Probability
A researcher measures the relationship between Internet use (hours per week) and social interaction (hours per week) in a sample of 10 students. The following table lists the hypothetical results of this study. Internet Use X = 6 8 5 6 13 5 4 5 3 10 Social Interaction Y= 4 5 7 7 4 7 2 6 9 4
(a) Compute the Pearson correlation coefficient. (Round your answer to three decimal places.)
(b) Compute the coefficient of determination. (Round your answer to three decimal places.)
(c) Using a two-tailed test at a 0.05 level of significance, state the decision to retain or reject the null hypothesis. Retain the null hypothesis?
Reject the null hypothesis?
(a) Compute the Pearson correlation coefficient. (Round your answer to three decimal places.)
-0.435
(b) Compute the coefficient of determination. (Round your answer to three decimal places.)
0.189
(c) Using a two-tailed test at a 0.05 level of significance, state the decision to retain or reject the null hypothesis.
Retain the null hypothesis.
X | Y | |||||
6 | 4 | |||||
8 | 5 | |||||
5 | 7 | |||||
6 | 7 | |||||
13 | 4 | |||||
5 | 7 | |||||
4 | 2 | |||||
5 | 6 | |||||
3 | 9 | |||||
10 | 4 | |||||
r² | 0.189 | |||||
r | -0.435 | |||||
Std. Error | 1.976 | |||||
n | 10 | |||||
k | 1 | |||||
Dep. Var. | Y | |||||
ANOVA table | ||||||
Source | SS | df | MS | F | p-value | |
Regression | 7.2758 | 1 | 7.2758 | 1.86 | .2093 | |
Residual | 31.2242 | 8 | 3.9030 | |||
Total | 38.5000 | 9 | ||||
Regression output | confidence interval | |||||
variables | coefficients | std. error | t (df=8) | p-value | 95% lower | 95% upper |
Intercept | 7.4303 | |||||
X | -0.2970 | 0.2175 | -1.365 | .2093 | -0.7985 | 0.2046 |
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