A random sample of 30 lunch orders at "El Sandwichero" showed a standard deviation of $5.31....

A random sample of 30 lunch orders at "El Sandwichero" showed a standard deviation of $5.31. You are in charge of creating a 90% confidence interval for the population variance.

What is the lower end of the confidence interval?

Expert Solution

So CI is (19.214,46.175)

orchestra answered 1 year ago

1) A random sample of 13 lunch orders at Noodles and Company showed a mean bill...

1) A random sample of 13 lunch orders at Noodles and Company showed a mean bill of $10.32 with a standard deviation of $4.62. Find the 99 percent confidence interval for the mean bill of all lunch orders. (Round your answers to 4 decimal places.) The 99% confidence interval is from 2) The Environmental Protection Agency (EPA) requires that cities monitor over 80 contaminants in their drinking water. Samples from the Lake Huron Water Treatment Plant gave the results shown...

21. The mean BMI from a random sample of 30 men is 31.3 with standard deviation...

21. The mean BMI from a random sample of 30 men is 31.3 with standard deviation ? = 4.6. Suppose the distribution of BMI is approximately normal. Construct a 95% confidence interval of the population mean BMI. 22. (5 Points) A medical researcher wants to investigate the amount of time it takes for patients' headache pain to be relieved after taking a new prescription painkiller. She believes that the population is normally distributed with a standard deviation of σ =...

. the contents of a sample of 26 cans of apple juice showed a standard deviation...

. the contents of a sample of 26 cans of apple juice showed a standard deviation of 0.06 ounces. We are interested in testing to determine whether the variance of the population is significantly more than .003. At 95% confidence, what is the critical value from the table?

1. A sample of 96 observations showed an average of 25 and a standard deviation of...

1. A sample of 96 observations showed an average of 25 and a standard deviation of 16. Construct the 90% confidence interval for the population mean. What is the lower limit of this interval? NOTE: WRITE YOUR ANSWER USING 4 DECIMAL DIGITS. DO NOT ROUND UP OR DOWN. 2. In a recent poll, from a sample of 140 likely voters, 65 answered they approve the way the president is handling his job. Compute the upper limit of the 95% confidence...

A sample of 30 observation has sample mean x̅ = 53 and sample standard deviation of...

A sample of 30 observation has sample mean x̅ = 53 and sample standard deviation of s = 3. Construct a 99% two sided confidence interval for the population mean. If we want the length of 99% two sided confidence interval to be smaller than 1, how many more samples do we need to take? Please show your work, I will be studying the solution step by step.

A sample has a mean of M = 30 and a standard deviation of s =...

A sample has a mean of M = 30 and a standard deviation of s = 8. Find the z-score for each of the following X values from this sample. X = 32 X = 34 X = 36 X = 28 X = 20 X = 18

Suppose ? is a random variable with mean ?=50 and standard deviation ?=49. A random sample...

Suppose ? is a random variable with mean ?=50 and standard deviation ?=49. A random sample of size ?=38 is selected from this population. a) Find ?(?¯<49).P(X¯<49). Round your answer to four decimal places. b) Find ?(X¯≥52).P(X¯≥52). Round your answer to four decimal places. c) Find ?(49.5≤X¯≤51.5).P(49.5≤X¯≤51.5). Give your answer to four decimal places. d) Find a value ?c such that ?(X¯>?)=0.15.P(X¯>c)=0.15. Round your answer to two decimal places.

The prices of a random sample of 2525 new motorcycles have a sample standard deviation of...

The prices of a random sample of 2525 new motorcycles have a sample standard deviation of $ 3749$3749. Assume the sample is from a normally distributed population. Construct a confidence interval for the population variance sigma squaredσ2 and the population standard deviation sigmaσ. Use a 99 % level of confidence. Interpret the results.

A sample of 225 American males showed a mean lifetime of 69.8 years, standard deviation of...

A sample of 225 American males showed a mean lifetime of 69.8 years, standard deviation of 4.3 years. Give 99.73% confidence limits for the mean lifetime of American males.

A study regarding pizza eaters showed that in a random sample of 21 individuals, the standard...

A study regarding pizza eaters showed that in a random sample of 21 individuals, the standard deviation for the number of slices of pizza an individual can eat is 1.3 slices. Find the 90% confidence interval of the variance and the standard deviation. Show your work to receive credit.

Question