In: Statistics and Probability
The University of Avalon (U of A) wants to know how much credit card debt students typically have when they graduate. A survey of 32 recent graduates indicated that the mean debt was 2430 pounds with a standard deviation of 1850 pounds. Find a 99% confidence interval for the average credit card debt for all recent U of A graduates. Assume the credit card debt is normally distributed.
Round answers to 2 decimal places.
Use the tables in the book and not an outside source.
Please show work for the opportunity to earn partial credit on this question.
Solution :
Given that,
Point estimate = sample mean = = 2430
sample standard deviation = s = 1850
sample size = n = 32
Degrees of freedom = df = n - 1 = 32 - 1 = 31
At 99% confidence level
= 1 - 99%
=1 - 0.99 =0.01
/2
= 0.005
t/2,df
= t0.005,31 = 2.744
Margin of error = E = t/2,df * (s /n)
= 2.744 * ( 1850 / 32 )
Margin of error = E = 897.39
The 99% confidence interval estimate of the population mean is,
± E
= 2430 ± 897.39
= ( 1532.61, 3327.39 )