In: Physics
A particle of mass 0.000117 g and charge 15 mC moves in a region of space where the electric field is uniform and is 4.5 N/C in the x direction and zero in the y and z direction. If the initial velocity of the particle is given by vy = 3.6 × 10^5 m/s, vx = vz = 0, what is the speed of the particle at 0.7 s? Answer in units of m/s.
If the particle experience a costant force then theacceleration along the y direction is
ay = e E / m
= (15×10-3 C)(4.5 N/C) / (1.17*10-7 kg )
= 5.76×105 m/s2
Using the equation Vy = Voy+ ay t
Vy= ayt [ Voy = 0]
= (5.76×105 m/s2 )(0.7s)
= 4.03×105 m/s
As Vx and Vz =0 so the speed is 4.03×105 m/s