A particle of mass 0.000117 g and charge 15 mC moves in a region of space...

A particle of mass 0.000117 g and charge 15 mC moves in a region of space where the electric field is uniform and is 4.5 N/C in the x direction and zero in the y and z direction. If the initial velocity of the particle is given by vy = 3.6 × 10^5 m/s, vx = vz = 0, what is the speed of the particle at 0.7 s? Answer in units of m/s.

Solutions

Expert Solution

If the particle experience a costant force then theacceleration along the y direction is

a_y = e E / m

= (15×10^-3 C)(4.5 N/C) / (1.17*10^-7 kg )

= 5.76×10⁵ m/s²

Using the equation V_y = V_oy+ a_y t

V_y= a_yt [ V_oy = 0]

= (5.76×10⁵ m/s² )(0.7s)

= 4.03×10⁵ m/s

As Vx and Vz =0 so the speed is 4.03×10⁵ m/s

genius_generous answered 1 year ago

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