Question

In: Statistics and Probability

An SRS produced the following data. Is browser choice and grade level independent? The responses were...

An SRS produced the following data. Is browser choice and grade level independent? The responses were categorized below. Test at the .05 significance level. (α = .05)

Safari

Firefox

Chrome

Freshmen

20

25

40

Sophomore

40

30

30

Junior

50

25

50

Senior

90

20

75

What is your conclusion in plain English?

a) There is not enough evidence to suggest that browser choice and grade level are dependent.

b) Evidence suggests that browser choice and grade level are independent.

c) There is not enough evidence to suggest that browser choice and grade level are independent.

d) Evidence suggests that browser choice and grade level are dependent.

Solutions

Expert Solution

ANSWER::

Expected frequency of a cell = sum of row*sum of column / total sum
Expected Frequencies
Total
200*85/495=34.343 100*85/495=17.172 195*85/495=33.485 85
200*100/495=40.404 100*100/495=20.202 195*100/495=39.394 100
200*125/495=50.505 100*125/495=25.253 195*125/495=49.242 125
200*185/495=74.747 100*185/495=37.374 195*185/495=72.879 185
(fo-fe)^2/fe
5.990 3.569 1.268
0.004 4.752 2.240
0.0051 0.0025 0.0117
3.1123 8.0764 0.0617

Chi-Square Test Statistic,χ² = Σ(fo-fe)^2/fe =   29.093                          
                              
Level of Significance =   0.05                          
Number of Rows =   4                          
Number of Columns =   3                          
Degrees of Freedom=(#row - 1)(#column -1) = (4- 1 ) * ( 3- 1 ) =   6                          
                              
p-Value =   0.0001   [Excel function: =CHISQ.DIST.RT(χ²,df) ]                      
Decision:    p-value < α , Reject Ho                          

Option:: (d) is correct...........

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