In: Statistics and Probability
Solution
Given that,
= 215620
= 38790
n = 400
At 98% confidence level the z is ,
=
1 - 98% = 1 - 0.98 = 0.02
/ 2 = 0.02 / 2 = 0.01
Z/2
= Z0.01= 2.326
Margin of error = E = Z/2*
(
/n)
= 2.326* (38790/
400 )
= 4512
At 98% confidence interval estimate of the population mean is,
- E <
<
+ E
215620 - 4512 <
< 215620 + 4512
211108 <
< 220132
(211108, 220132)