In: Statistics and Probability
a) A researcher claims that the mean age of CEOs (chief executive officers) of all corporations in the United States is 4646 years. A sample of 5050 corporations showed that the mean age of their CEOs is 48.348.3 years with a standard deviation of 5.55.5 years. Find the pp-value for the test that the mean age of CEOs of all corporations is different from 4646 years at αα = 0.0020.002.
b) The manager of a bank claims that the mean waiting time for all customers at that bank is not more than 1212 minutes. A sample of 2020 customers who visited this bank gave a mean waiting time of 14.7514.75 minutes and a standard deviation of 3.43.4 minutes. Test at the 2.5%2.5% significance level if the mean waiting time for all customers who visit this bank is greater than 1212 minutes. State the assumption(s) required for the test.
## a ) A researcher claims that the mean age of CEOs (chief executive officers) of all corporations in the United States is 46 years. A sample of 50 corporations showed that the mean age of their CEOs is 48.3 years with a standard deviation of 5.5 years. Find the pp-value for the test that the mean age of CEOs of all corporations is different from 46 years at αα = 0.002.
Answer :
we have given :
n = sample size = 50
x̄ = sample mean = 48.3
μ = population mean = 46
s = sample standard deviation = 5.5
α = 0.2 % = 0.002
Claim : Test to determine if the mean age of CEOs of all corporations is different from 46 years
## step1 : null and alternative Hypothesis :
Ho : μ = 46 vs H1: μ ≠ 46
( it is two tailed test )
## step 2 : Test statistics :
t = (x̄ - μ) * sqrt ( n ) / s
t = ( 48.3 - 46 ) * sqrt (50) / 5.5
= 16.2634 / 5.5
= 2.9569
## step 3 : level of significance = 0.002
## step 4 : P value : it is two tailed test :
df = degree of freedom = n -1 = 49
= 2 * P ( t > 2.9569) ( use statistical table )
= 2 * 0.002391
= 0.004782
step 5 : Decision :
We reject Ho if p value is less than alpha value using p value
approach here
p value is greater than alpha value we
fail to reject Ho at given level of significance
.
Step 6 : Conclusion :
There is Insufficient evidence to conclude that the mean age of CEOs of all corporations
is different from 46 years .
that is we accept Ho , and mean is equal to 46 .
### b) The manager of a bank claims that the mean waiting time for all customers at that bank is not more than 1212 minutes. A sample of 2020 customers who visited this bank gave a mean waiting time of 14.7514.75 minutes and a standard deviation of 3.43.4 minutes. Test at the 2.5%2.5% significance level if the mean waiting time for all customers who visit this bank is greater than 1212 minutes. State the assumption(s) required for the test.
Answer : we have given :
n = sample size = 20
x̄ = sample mean = 14.75
μ = population mean = 12
s = sample standard deviation = 3.4
α = 2.5 % = 0.025
Claim : Test to determine if the mean waiting time for all customers who visit this bank is greater than 12 minutes .
# it is one sample t test : here sample size < 30 and population variance unknown here all the assumptions or condition satisfy for t test hence it used .
## step1 : null and alternative Hypothesis :
Ho : μ = 12 vs H1: μ > 12
( it is one tailed test , right tailed test )
## step 2 : Test statistics :
t = (x̄ - μ) * sqrt ( n ) / s
t = ( 14.75 - 12 ) * sqrt (20) / 3.4
= 12.2983 / 3.4
= 3.6171
## step 3 : level of significance = 0.025
## step 4 : P value : it is one tailed test :
df = degree of freedom = n -1 = 19
= P ( t > 3.6171) ( use statistical table )
= 0.00091
step 5 : Decision :
We reject Ho if p value is less than alpha value using p value
approach here
p value is less than alpha value we reject
Ho at given level of significance .
Step 6 : Conclusion :
There is sufficient evidence to conclude that the mean waiting time for all customers who visit this bank is greater than 12 minutes .