In: Physics
A 8.0-cm-diameter horizontal pipe gradually narrows to 5.0 cm . When water flows through this pipe at a certain rate, the gauge pressure in these two sections is 31.0 kPa and 25.0 kPa , respectively. What is the volume rate of flow?
Given is:-
Initial diameter = 8cm
Final diameter = 5cm
Initital Pressure P1 = 31KPa
Final Pressure P2 = 25KPa
Initial Area of the pipe is
Final area of the pipe is
We know that the flow rates must be the same as water is incompressible
or
By putting all the details in above equation, we get
Now by the Bernoulli's theroem
we haven't written potential energy terms because pipe is at same height, thus P.E will remain same.
By putting all the terms in above equation we get
Thus will be
Thus the volume rate of flow will be area multiplied by veloctiy
Initial or
similarly the final flow rate will be
(Because flow rate will be remain same)