Question

The owner of a fish market has an assistant who has determined that the weights of catfish are normally distributed, with mean of 3.2 pounds and standard deviation of 0.8 pound.

A)  If just one fish is taken, what would the standard error of the mean weight equal?

B) If a sample of 4 fish is taken, what would the standard error of the mean weight equal?

Answer 1

Solution :

Given that ,

mean = = 3.2

standard deviation = = 0.8

n = 1

sampling distribution of standard deviation

=  / n = 0.8 / 1

= 0.8

b

sampling distribution of standard deviation

=  / n = 0.8 / 4

= 0.4