In: Statistics and Probability
Question: For each of the following scenarios, conduct the complete hypothesis testing process as appropriate give that scenario.
A regional manager implements a policy change for stores in his region to begin greeting customers whenever they are standing within a 3 metre distance in the store. He compares mean daily purchase numbers over one month from pre-change to post-change for each store to see if the change makes a difference in sales.
Mean daily purchases for Store 1 through Store 10 before policy: 82, 103, 91, 91, 83, 76, 90, 114, 88, 92
Mean daily purchases for Store 1 through Store 10 after policy: 102, 83, 113, 87, 94, 78, 91, 117, 101, 107
Ho : µd= 0
Ha : µd ╪ 0
Sample #1 | Sample #2 | difference , Di =sample1-sample2 | (Di - Dbar)² |
82 | 102 | -20.000 | 187.69 |
103 | 83 | 20.000 | 691.69 |
91 | 113 | -22.000 | 246.49 |
91 | 87 | 4.000 | 106.09 |
83 | 94 | -11.000 | 22.09 |
76 | 78 | -2.000 | 18.49 |
90 | 91 | -1.000 | 28.09 |
114 | 117 | -3.000 | 10.89 |
88 | 101 | -13.000 | 44.89 |
92 | 107 | -15.000 | 75.69 |
sample 1 | sample 2 | Di | (Di - Dbar)² | |
sum = | 910 | 973 | -63 | 1432.1 |
mean of difference , D̅ =ΣDi / n =
-6.300
std dev of difference , Sd = √ [ (Di-Dbar)²/(n-1) =
12.6144
std error , SE = Sd / √n = 12.6144 /
√ 10 = 3.9890
t-statistic = (D̅ - µd)/SE = ( -6.3
- 0 ) / 3.9890
= -1.579
Degree of freedom, DF= n - 1 =
9
p-value = 0.14872
[excel function: =t.dist.2t(t-stat,df) ]
Conclusion: p-value>α=0.05 , Do not reject
null hypothesis
There is not enough evidence to conclude that the change makes a difference in sales at α=0.05