In: Statistics and Probability
The Damon family owns a large grape vineyard in western New York along Lake Erie. The grapevines must be sprayed at the beginning of the growing season to protect against various insects and diseases. Two new insecticides have just been marketed: Pernod 5 and Action. To test their effectiveness, three long rows were selected and sprayed with Pernod 5, and three others were sprayed with Action. When the grapes ripened, 440 of the vines treated with Pernod 5 were checked for infestation. Likewise, a sample of 360 vines sprayed with Action were checked. The results are:
Insecticide | Number of Vines Checked (sample size) | Number of Infested Vines |
Pernod 5 | 440 | 36 |
Action | 360 | 30 |
At the 0.05 significance level, can we conclude that there is a difference in the proportion of vines infested using Pernod 5 as opposed to Action? Hint: For the calculations, assume the Pernod 5 as the first sample.
1. State the decision rule.
2. Compute the pooled proportion
3. Compute the value of the test statistic
4. What is your decision regarding the null hypothesis?
Reject
Fail to reject
Given:
The Damon family owns a large grape vineyard in western New York along Lake Erie.
When the grapes ripened, 440 of the vines treated with Pernod 5 were checked for infestation. Likewise, a sample of 360 vines sprayed with Action were checked. The results are:
Insecticide | Number of Vines Checked (sample size) | Number of Infested Vines |
Pernod 5 | 440 | 36 |
Action | 360 | 30 |
X1 = 36 n1 = 440
X2 = 30 n2 = 360
Hypothesis test:
The null and alternative hypothesis is
Ho : p1 = p2
Ha : P1 p2
At 0.05 significance level the critical value of Z is
Z/2 = Z0.05/2 = 1.96
1) Dicision rule :
Reject Ho, if Z > 1.96 or Z < -1.96 otherwise fail to reject.
Fail to reject the null hypothesis.
At the 0.05 significance level, we can not conclude that there is a difference in the proportion of vines infested using Pernod 5 as opposed to Action.