Question

What is the production of ATP both directly and through electron transport/oxidative phosphorylation when:

(i)       one mole of glucose is converted to two moles of acetyl CoA.

(ii)       one mole of acetyl CoA is metabolised to CO₂ and H₂O via the citric acid cycle.

(iii)       one mole of glucose is completely metabolised to CO₂ and H₂O via glycolysis, the pyruvate dehydrogenase reaction and the citric acid cycle.

How do you calculate this?

Answer 1

	Direct ATP (Substrate level of phosphorelation)	through electron transport/oxidative phosphorylation
one mole of glucose is converted to two moles of acetyl CoA.	2 (from glycolysis Substrate level of phosphorelation)	12 (2NADH from glycoslysis and 2 from pyruvate dehydrogenase reaction; 4*3 = 12)
one mole of acetyl CoA is metabolised to CO2 and H2O via the citric acid cycle.	1 (from glycolysis Substrate level of phosphorelation)	11 (3 NADH from TCA cycle, 1 FADH from TCA cycle; 3*3 = 9 + 1*2 = 2; total 9+2 = 11)
One mole of glucose is completely metabolised to CO2 and H2O via glycolysis, the pyruvate dehydrogenase reaction and the citric acid cycle.	4 (2 from from glycolysis Substrate level of phosphorelation, 2 from TCA Substrate level of phosphorelation)	34 (10 NADH (2 from glycolysis, 2 from pyruvate dehydrogenasereaction and 6 from TCA cycle) + 2 FADH (from TCA cycle) = 10*3 = 30+ 2*2 = 4; total : 34)

Answered by considering as 1NADH = 3 ATP; 1 FADH = 2 ATP