In: Computer Science
arms64 assembly language
Write a function to read a Sudoku board from an input string.
The input string must be exactly 81 characters long (plus the
terminating null that marks the end of the string) and contains
digits and dots (the `.` character represents an unmarked position).
The input contains all 9 rows packed together. For example, a Sudoku
board that looks like this:
```
..7 ... ...
6.4 ... ..3
... .54 ..2
... .4. ...
9.. ... ..5
385 ..2 ...
... ..3 78.
49. 71. ...
1.. ..8 9..
```
would be input as the string
```
"..7......6.4.....3....54..2....4....9.......5385..2........378.49.71....1....89.."
```
The function must read the board into an array of 81 bytes, with the
value 0 (*not* the digit `'0'`) for unfilled positions (represented
by dots in the input) and the values 1 through 9 (*not* the digits
`'1'` through `'9'`) for filled positions.
As it reads, the function should validate the input. If it is too
short, it should return 1. If it encounters an invalid character
(not a dot or a digit) then it should return 2. If the string is too
long it should return 3.
The following pseudocode should form the basis of your function:
```
def read_board(input, board):
for i = 0; i < 81; i++
ch = input[i]
// was the input too short?
if ch == 0:
return 1
// was it an unfilled square?
else if ch == '.':
board[i] = 0
// was it a filled square?
else if ch >= '1' and ch <= '9':
board[i] = ch - '0'
// anything else is invalid
else:
return 2
// was the input too long?
if input[i] != 0:
return 3
// success
return 0
```
Note that `input` and `board` are both memory addresses. We
interpret `input` as a string (the address is where the string
begins in memory, and it ends with the first zero byte found in the
string) and we interpret `board` as an array of bytes with 81
entries, where each byte is used as a small integer.
# HERE We USES partially filled 9×9 2D array ‘grid[9][9]’, the goal is to assign digits (from 1 to 9)
#to the empty cells so that every row, column, and subgrid
# of size 3×3 contains exactly one instance of the digits from 1 to 9.
# A Backtracking program in Python to solve Sudoku problem
# A Utility Function to print the Grid
def print_grid(arr):
for i in range(9):
for j in range(9):
print arr[i][j],
print ('n')
# Function to Find the entry in the Grid that is still not used
# Searches the grid to find an entry that is still unassigned. If
# found, the reference parameters row, col will be set the location
# that is unassigned, and true is returned. If no unassigned entries
# remains, false is returned.
# 'l' is a list variable that has been passed from the solve_sudoku function
# to keep track of incrementation of Rows and Columns
def find_empty_location(arr, l):
for row in range(9):
for col in range(9):
if(arr[row][col]== 0):
l[0]= row
l[1]= col
return True
return False
# Returns a boolean which indicates whether any assigned entry
# in the specified row matches the given number.
def used_in_row(arr, row, num):
for i in range(9):
if(arr[row][i] == num):
return True
return False
# Returns a boolean which indicates whether any assigned entry
# in the specified column matches the given number.
def used_in_col(arr, col, num):
for i in range(9):
if(arr[i][col] == num):
return True
return False
# Returns a boolean which indicates whether any assigned entry
# within the specified 3x3 box matches the given number
def used_in_box(arr, row, col, num):
for i in range(3):
for j in range(3):
if(arr[i + row][j + col] == num):
return True
return False
# Checks whether it will be legal to assign num to the given row, col
# Returns a boolean which indicates whether it will be legal to assign
# num to the given row, col location.
def check_location_is_safe(arr, row, col, num):
# Check if 'num' is not already placed in current row,
# current column and current 3x3 box
return not used_in_row(arr, row, num) and not used_in_col(arr, col, num) and not used_in_box(arr, row - row % 3, col - col % 3, num)
# Takes a partially filled-in grid and attempts to assign values to
# all unassigned locations in such a way to meet the requirements
# for Sudoku solution (non-duplication across rows, columns, and boxes)
def solve_sudoku(arr):
# 'l' is a list variable that keeps the record of row and col in find_empty_location Function
l =[0, 0]
# If there is no unassigned location, we are done
if(not find_empty_location(arr, l)):
return True
# Assigning list values to row and col that we got from the above Function
row = l[0]
col = l[1]
# consider digits 1 to 9
for num in range(1, 10):
# if looks promising
if(check_location_is_safe(arr, row, col, num)):
# make tentative assignment
arr[row][col]= num
# return, if success, ya ! if(solve_sudoku(arr)):
return True
# failure, unmake & try again
arr[row][col] = 0
# this triggers backtracking
return False
# Driver main function to test above functions
if __name__=="__main__":
# creating a 2D array for the grid
grid =[[0 for x in range(9)]for y in range(9)]
# assigning values to the grid
grid =[[3, 0, 6, 5, 0, 8, 4, 0, 0],
[5, 2, 0, 0, 0, 0, 0, 0, 0],
[0, 8, 7, 0, 0, 0, 0, 3, 1],
[0, 0, 3, 0, 1, 0, 0, 8, 0],
[9, 0, 0, 8, 6, 3, 0, 0, 5],
[0, 5, 0, 0, 9, 0, 6, 0, 0],
[1, 3, 0, 0, 0, 0, 2, 5, 0],
[0, 0, 0, 0, 0, 0, 0, 7, 4],
[0, 0, 5, 2, 0, 6, 3, 0, 0]]
# if success print the grid
if(solve_sudoku(grid)):
print_grid(grid)
else:
print "No solution exists"
#END OF CODE---
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