A 10.010.0 mL sample of whiskey was diluted to 500.0 mL. A 4.004.00 mL aliquot of...

A 10.010.0 mL sample of whiskey was diluted to 500.0 mL. A 4.004.00 mL aliquot of the diluted sample was removed and the ethanol, C2H5OHC2H5OH , was distilled into 50.00 mL of 0.022500.02250 M K2Cr2O7K2Cr2O7 and oxidized to acetic acid.

3C2H5OH+2Cr2O2−7+16H+⟶4Cr3++3CH3COOH+11H2O3C2H5OH+2Cr2O72−+16H+⟶4Cr3++3CH3COOH+11H2O

The excess Cr2O2−7Cr2O72− was then back titrated with 23.523.5 mL of 0.13300.1330 M Fe2+Fe2+ , producing Cr3+Cr3+ and Fe3+Fe3+ . Calculate the weight per volume percent (% w/v) of ethanol in the original whiskey sample.

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queen_honey_blossom answered 1 year ago

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