10.41 predict the geometries of the following A) SaCl53 B) PF62 C) CIF22 D) IF42

10.41 predict the geometries of the following

A) SaCl₅³

B) PF₆²

C) CIF₂²

D) IF₄²

Solutions

Expert Solution

I think you have errorneously written the anions so I am giving as per norms

A. There is no such structure may be typo error

B. PF₆^- : Central atom phosphorus has 5 valence electrons and 1 extra for negative charge making total of 6

there are 6 F so there will be 6 P-F sigma bond hence the geometry will be octaheral

C. ClF₂^- : Central atom Chlorine has 7 valence electrons and 1 extra for negative charge making total of 8

there are 2 F so there will be 2 Cl-F sigma bond leaving 6 electron which exist as 3 lone pair hence the geometry will be (2+3) hence the geometry will be trigonal bipyramidal and molecular shape will be linear

D. IF4^- The electron geometry of IF4+ will be octahedral and shape will be square planar.

Central atom Iodine has 7 valence electrons and 1 plus for negative charge making total of 8

there are 4 F so there will be 4 I-F sigma bond leaving 4 electron which exist as 2 lone pair hence the geometry will be (4+2)

queen_honey_blossom answered 1 year ago

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