A current carrying gold wire has diameter of 0.84 mm. the electric field in the wire...

A current carrying gold wire has diameter of 0.84 mm. the electric field in the wire is 0.49 V/m. What is

a The current carried by the wire?

b The potential difference between two points in the wire 6.4 m apart?

c The resistance of a 6.4 m length of this wire.

Expert Solution

g

genius_generous answered 2 years ago

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