The surface energy of a single crystal depends on crystallographic orientation. Does this surface energy increase...

The surface energy of a single crystal depends on crystallographic orientation. Does this surface energy increase or decrease with an increase in planar density? Why? (Hint: Read “External Surface” part in S.4.6: Surface energy is proportional to the number of unsatisfied bonds of surface atoms)

please clear hand writing, also plesae don't give me the book answer.

Thank you.

Expert Solution

As the atomic pachup is different for various crystallographic planes, the number of unsatisfied bonds (Ehich determine surface energy) also change from plane to plane.

The surface energy of a single crystal depends on the planar density i.e., degree of atomic packing) of the exposed surface plane because of the number of unsatisfied bonds. As the planar density increases, the number of nearest atoms in the plane increases, which results in an increase in the number of satisfied atomic bonds in the plane, and a decrease in the number of unsatisfied bonds. Since the number of unsatisfied bonds diminishes, so also does the surface energy decrease. (That is, surface energy decreases with an increase in planar density).

samet mamat answered 2 years ago

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