In: Statistics and Probability
Of 100 randomly selected people in Oregon, 45 said they were going to vote yes on Proposition 1.
Construct a 95% confidence interval and round answers to 3 decimal places _____,____ (i.e. 0.123)
Level of Significance, α =
0.05
Number of Items of Interest, x =
45
Sample Size, n = 100
Sample Proportion , p̂ = x/n =
0.450
z -value = Zα/2 = 1.960 [excel
formula =NORMSINV(α/2)]
Standard Error , SE = √[p̂(1-p̂)/n] =
0.0497
margin of error , E = Z*SE = 1.960
* 0.0497 = 0.0975
95% Confidence Interval is
Interval Lower Limit = p̂ - E = 0.450
- 0.0975 = 0.3525
Interval Upper Limit = p̂ + E = 0.450
+ 0.0975 = 0.5475
so, confidence interval is ( 0.352 < p
< 0.548 )