In: Accounting
BSU Inc. wants to purchase a new machine for $33,680, excluding
$1,300 of installation costs. The old machine was bought five years
ago and had an expected economic life of 10 years without salvage
value. This old machine now has a book value of $2,100, and BSU
Inc. expects to sell it for that amount. The new machine would
decrease operating costs by $8,000 each year of its economic life.
The straight-line depreciation method would be used for the new
machine, for a six-year period with no salvage value.
(a)
Determine the cash payback period. (Round cash payback
period to 2 decimal places, e.g. 10.53.)
Cash payback period _______years
(b)
Determine the approximate internal rate of return.
(Round answer to 0 decimal places, e.g. 13%. For
calculation purposes, use 5 decimal places as displayed in the
factor table provided.)
Internal rate of return ________%
a)
cash outflow for machine
purchase of new machine | $33,680 |
installation cost | $1300 |
book value of old machine | (2100) |
Net cash outflow | 32,880$ |
cash pay back period
=cash outflow/ cash saving per year
=32880$/8000$
=4.11 Years.
2.we will find NPV at 2 random rates
=NPV = present value of cash inflow- cash outflow
NPV1 = 10%
years | cash flow | PV FACTOR AT 10% | present value | |
0 | (32880) | 1 | (32880) | |
1 | 8000 | 0.90909[1/1.10]1 | 7272.72 | |
2 | 8000 | 0.82645[1/1.10]2 | 6611.6 | |
3 | 8000 | 0.75131[1/1.10]3 | 6010.48 | |
4 | 8000 | 0.68301[1/1.10]4 | 5464.08 | |
5 | 8000 | 0.62092[1/1.10]5 | 4967.36 | |
6 | 8000 | 0.56447[1/1.10]6 | 4515.76 | |
NPV | 1962$ | [7272.72+6611.6+6010.48+5464.08+4967.36+4515.76-32880] |
NPV2 = 15%
years | cash flow | PV FACTOR AT 15% | present value | |
0 | (32880) | 1 | (32880) | |
1 | 8000 | 0.86957[1/1.15]1 | 6956.56 | |
2 | 8000 | 0.75614[1/1.15]2 | 6049.12 | |
3 | 8000 | 0.65752[1/1.15]3 | 5260.16 | |
4 | 8000 | 0.57175[1/1.15]4 | 4574 | |
5 | 8000 | 0.49718[1/1.15]5 | 3977.44 | |
6 | 8000 | 0.43233[1/1.15]6 | 3458.64 | |
NPV | $(2604.08) | [6956.56+6049.12+5260.16+4574+3977.44+3458.64-32880] |
IRR = R1 + [NPV 1*(R2-R1)]/(NPV1-NPV2)
= 0.10+[(1962 (0.15-0.10)]/(1962 - (-2604.08)
=0.10 + (98.1/4566.08)
=0.10+0.02148
=12%