Question

A Copper plate that is 588mm wide and 48 mm thick is to be reduced in a single pass in a two high rolling mill by using a 321mm diameter roll. The coefficient of friction at roll workpiece interface is  0.14 and the roll rotates at 107rpm. The rolling process is performed above the recrystallization temperature of the material and the width of the plate does not change during this operation. What is the minimum final thickness (mm) possible

Answer 1

There are several ways to solve this question,

But, I will keep it quick using single formula

t₁ = initial thickness = 48 mm = 0.048 m

t₂ = t_f = final thickness =?

R = radius of roller = D/2 = (0.321) / 2 = 0.1605 m

µ = coefficient of friction = 0.14

lets put all the values,

Solving for t_f gives us

t_f = t₂ = 0.04485 m = 44.85 mm

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If you want something else please let me know in comment

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