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copper fin 1.0 mm thick is placed on a circular tube. The out side daiameter of...
copper fin 1.0 mm thick is placed on a circular tube. The out side daiameter of the tube is 2.5 cm. The fin long is 8 mm and the thermal conductivity is 379 W/m °C. The tube wall is maintained at 473K. The fin is exposed to an environment with h = 30 W/m "C and T∞= 288K. %3D Calculate the heat lost by the fin.
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Amanda K answered 1 year agoRelated Solutions
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Consider a 9 mm diameter circular tube, calculate the length of tube that is required to...
Consider a 9 mm diameter circular tube, calculate the length of tube that is required to transfer 100 W of
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The temperature of the water is kept constant at 50 ° C and the wall
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A tube with a diameter of 6.45 mm was placed in a liquid with a density...
A tube with a diameter of 6.45 mm was placed in a liquid with a density of 998 kg / m3 and it was observed that the liquid increased by 1.44 mm in the tube. Find the surface tension of the fluid [N / m] by taking the contact angle 15 ° between the liquid and the tube surface.
A tube has a diameter of 0.87 mm and is placed vertically in a liquid of...
A tube has a diameter of 0.87 mm and is placed vertically in a
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A copper wire has a radius of 1.0 mm. What is the resistance of
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500 mm thick square footing is to be placed at a depth of 0.5 m in...
500 mm thick square footing is to be placed at a depth of 0.5 m
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500 mm thick square footing is to be placed at a depth of 0.5 m in...
500 mm thick square footing is to be placed at a depth of 0.5 m
in a clayey sand where c¢ = 10 kPa, f¢ = 34°, g = 19.0 kN/m3. The
column load to be applied on the footing is 2000 kN. What should be
the width of the footing? please show each steps with how you
solved to obtain value of B
500 mm thick square footing is to be placed at a depth of 0.5 m in...
500 mm thick square footing is to be placed at a depth of 0.5 m
in a clayey sand where c¢ = 10 kPa, f¢ =
34°, g = 19.0 kN/m3. The column load to be
applied on the footing is 2000 kN. What should be the width of the
footing?
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