A point of charge q is placed at the point (-d,0) and a second point charge...

A point of charge q is placed at the point (-d,0) and a second point charge of charge 2q is placed at point (2d,0). a) What is the force on the third charge of charge -q placed at point (0,d) if d=190nm and q=250nC? b) find the two positive charges placed on the x-axis? c) What is the electric field at the origin?

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genius_generous answered 1 year ago

A point charge q1 = 4.00 nC is placed at the origin, and a second point...

A point charge q1 = 4.00 nC is placed at the origin, and a second point charge q2 = -3.10 nC is placed on the x-axis at x=+ 20.0 cm . A third point charge q3 = 1.95 nC is to be placed on the x-axis between q1 and q2. (Take as zero the potential energy of the three charges when they are infinitely far apart.) 1:What is the potential energy of the system of the three charges if q3...

A cube with side a is located at the origin,a point charge q is placed at...

A cube with side a is located at the origin,a point charge q is placed at each vertex .find the charge density in term of Dirac delta function

(a) A positive point charge Q is placed at the center of a cube. Draw the...

(a) A positive point charge Q is placed at the center of a cube. Draw the field lines for this charge configuration. Include at least 7 field lines and be sure to show them passing through the surface of the cube. (b) What is the flux through one side of this cube? Hint: Do not under any circumstances integrate to find the flux. Think about how many sides the cube has and whether or not the flux through each face...

A positive charge q is fixed at the point x = 0, y = 0, and...

A positive charge q is fixed at the point x = 0, y = 0, and a negative charge -2q is fixed at the point x = a, y = 0. a) Derive an expression for the potential V at points on the x -axis as a function of the coordinate x . Take V to be zero at an infinite distance from the charges. (Express your answer in terms of the given quantities and appropriate constants). V(x) = b)...

Three point charges are placed on the y-axis, a charge q at y=a, a charge -2q...

Three point charges are placed on the y-axis, a charge q at y=a, a charge -2q at the origin and a charge q at y=-a. Such an arrangement is called an electric quadrupole. (a) Find the magnitude and direction of the electric field at points on the positive x-axis. (b)What would be the force exerted by these three charges on a fourth charge 2q placed at (b,0). Explain the steps along the way and thought process behind solving.

A positive charge q is fixed at the point x=0,y=0 and a negative charge -2q is...

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A point particle with charge q = 4.2 ?C is placed on the x axis at...

A point particle with charge q = 4.2 ?C is placed on the x axis at x = ?10 cm and a second particle of charge Q = 7.8 ?C is placed on the x axis at x = +25 cm. (a) Determine the x and y components of the electric field due to this arrangement of charges at the point (x, y) = (10, 10) (the units here are centimeters). Ex = N/C Ey = N/C (b) Determine the magnitude and...

A point charge of is at the origin, and a second point charge of +6.00nC is...

A point charge of is at the origin, and a second point charge of +6.00nC is on the x axis at x=0.800m Find the magnitude and direction of the electric field at each of the following points on the x axis a)x=20.0cm b)x=1.20m c) -20.0cm so, since its electric field question using e=k*q/r^2 i can solve this so, e= (k*q/r^2) + (k*q/r^2) so, +6.00nC is on the x axis at x=0.800m.... and -4.00nC is at the origin.. so 0. a)...

In a rectangular coordinate system, a positive point charge q = 7.50 nC is placed at...

In a rectangular coordinate system, a positive point charge q = 7.50 nC is placed at the point x= 0.180 m , y=0, and an identical point charge is placed at x= -0.180 m , y=0. Find the x and y components and the magnitude and direction of the electric field at the following points. a. Find the x and y components of the electric field at the origin. b. Find the magnitude of the electric field at the origin....

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