In: Chemistry
Menthol is a crystalline substance with a peppermint taste and odor. When 1.19 g of menthol is dissolved in 25.0 g of cyclohexane, the freezing point of the solution is lowered by 6.34 ∘ C. Look up the freezing point and K f constant for cyclohexane in the Colligative Constants table. Calculate the molar mass of menthol.
Solvent | Formula | Kf value*
(°C/m) |
Normal freezing point (°C) |
Kb value
(°C/m) |
Normal boiling point (°C) |
water | H2O | 1.86 | 0.00 | 0.512 | 100.00 |
benzene | C6H6 | 5.12 | 5.49 | 2.53 | 80.1 |
cyclohexane | C6H12 | 20.8 | 6.59 | 2.92 | 80.7 |
ethanol | C2H6O | 1.99 | –117.3 | 1.22 | 78.4 |
carbon tetrachloride |
CCl4 | 29.8 | –22.9 | 5.03 | 76.8 |
camphor | C10H16O | 37.8 | 176 |
Mass of menthol is 1.19 g
Menthol is a non-electrolyte and hence has van't Hoff factor, i =1.
Now, the depression in freezing point for the solution is given as
Now, the depression in freezing point is calculated as follows:
Where i = van't Hoff factor of the solute (here for menthol, i = 1)
molal freezing point depression constant of solvent (for cyclohexane, )
molality is the moles of solute per kg of solvent where 1 mol/kg = 1 m
Now, we can write
Hence, the molality of the solution is 0.3048 mol/kg.
i.e. there are 0.3048 moles of menthol per kg of cyclohexane.
Given that the mass of cyclohexane = 25.0 g = 0.0250 kg, we can calculate the moles of menthol present in the solution as follows:
Hence, 0.00762 mol of menthol must be equivalent to 1.19 g of menthol.
Hence, the molar mass of menthol can be calculated as
Hence, the molar mass of menthol is about 156.2 g/mol.