Question

The International League of Triple-A minor league baseball consists of 14 teams organized into three divisions: North, South, and West. Suppose the following data show the average attendance for the 14 teams in the International League. Also shown are the teams' records; W denotes the number of games won, L denotes the number of games lost, and PCT is the proportion of games played that were won.

Team Name	Division	W	L	PCT	Attendance
Buffalo Bisons	North	66	77	0.462	8,815
Lehigh Valley IronPigs	North	55	89	0.382	8,472
Pawtucket Red Sox	North	85	58	0.594	9,093
Rochester Red Wings	North	74	70	0.514	6,918
Scranton-Wilkes Barre Yankees	North	88	56	0.611	7,148
Syracuse Chiefs	North	69	73	0.486	5,766
Charlotte Knights	South	63	78	0.447	4,528
Durham Bulls	South	74	70	0.514	6,995
Norfolk Tides	South	64	78	0.451	6,282
Richmond Braves	South	63	78	0.447	4,454
Columbus Clippers	West	69	73	0.486	7,796
Indianapolis Indians	West	68	76	0.472	8,539
Louisville Bats	West	88	56	0.611	9,153
Toledo Mud Hens	West	75	69	0.521	8,236

a) Use α = 0.05 to test for any difference in the mean attendance for the three divisions.

Find the value of the test statistic. (Round your answer to two decimal places.)

Find the p-value. (Round your answer to three decimal places.)

p-value =

b) use Fisher's LSD procedure to determine where the differences occur. Use α = 0.05.

Find the value of LSD for each pair of divisions. (Round your answers to two decimal places.)

North and South LSD =

North and West LSD =

South and West LSD =

Find the pairwise absolute difference between sample attendance means for each pair of divisions. (Round your answers to the nearest integer.)

x_N − x_S=

x_N − x_W=

x_S − x_W=

Answer 1

Solution:

Applying one way ANOVA:

a) value of the test statistic =6.97

p value =0.011

b)

Fisher's (LSD) for group i and j =(tN-k)*(sp*√(1/ni+1/nj)   =

North and South LSD = 1619.42

North and West LSD = 1619.42

South and West LSD = 2863.25

xN-xS	2136.92~ 2137
xN-xW	726.33~ 726
xS-xW	2863.25 ~2863

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