In: Statistics and Probability
Find the probability that in a family of 4 children there will be
a) At least 1 girl
b) At least 1 boy and at least 1 girl
c) Out of 1500 families with 3 children each how many would you expect to have 1 or 2 girls.
Assume that the probability of a female birth is 1/2.
Family of 4 children : Possibilities :
zero boys: 1/16;
one boy: 1/4
two boys: 3/8
three boys: 1/4
four boys: 1/16
Note: 1/16 + 1/4 + 3/8 + 1/4 + 1/16 = 1
a) Family of 4 children : Possibilities:
Prob(atleast 1 girl) = Prob(1 girl) + Prob(2 girls) + Prob(3 girls) + Prob(4 girls)
Prob(atleast 1 girl) = 1 - Prob(0 girls)
0 girls = 1 possibility (BBBB) out of 16 possibilities
Prob(atleast 1 girl) = 1 - 1/16 = 15/16
b) Prob(atleast 1 B and 1 G) = 1 - (BBBB, GGGG) = 1 - 2/16 = 14/16
c) 3 children - BBB, BBG, BGB, GBB, GGB, GBG, BGG, GGG
Prob ( 1 or 2 girls) = BBG, BGB, GBB, GGB, GBG, BGG = 6/8 = 3/4
Therefore, for 1500 families, 3/4 x 1500 = 1125 famillies