In: Statistics and Probability
A transect is an archaeological study area that is 1/5 mile wide and 1 mile long. A site in a transect is the location of a significant archaeological find. Let x represent the number of sites per transect. In a section of Chaco Canyon, a large number of transects showed that x has a population variance σ2 = 42.3. In a different section of Chaco Canyon, a random sample of 24 transects gave a sample variance s2 = 49.1 for the number of sites per transect. Use a 5% level of significance to test the claim that the variance in the new section is greater than 42.3. Find a 95% confidence interval for the population variance.
(a) What is the level of significance?
State the null and alternate hypotheses.
Ho: σ2 = 42.3; H1: σ2 > 42.3
Ho: σ2 = 42.3; H1: σ2 < 42.3
Ho: σ2 = 42.3; H1: σ2 ≠ 42.3
Ho: σ2 > 42.3; H1: σ2 = 42.3
(b) Find the value of the chi-square statistic for the sample.
(Round your answer to two decimal places.)
What are the degrees of freedom?
What assumptions are you making about the original
distribution?
We assume a uniform population distribution.
We assume a normal population distribution.
We assume a binomial population distribution.
We assume a exponential population distribution.
(c) Find or estimate the P-value of the sample test
statistic.
P-value > 0.100
0.050 < P-value < 0.100
0.025 < P-value < 0.050
0.010 < P-value < 0.025
0.005 < P-value < 0.010
P-value < 0.005
(d) Based on your answers in parts (a) to (c), will you reject or
fail to reject the null hypothesis?
Since the P-value > α, we fail to reject the null hypothesis.
Since the P-value > α, we reject the null hypothesis.
Since the P-value ≤ α, we reject the null hypothesis
.Since the P-value ≤ α, we fail to reject the null hypothesis.
(e) Interpret your conclusion in the context of the
application.
At the 5% level of significance, there is insufficient evidence to conclude conclude that the variance is greater in the new section.
At the 5% level of significance, there is sufficient evidence to conclude conclude that the variance is greater in the new section.
(f) Find the requested confidence interval for the population
variance. (Round your answers to two decimal places.)
lower limit | |
upper limit |
Interpret the results in the context of the application.
We are 95% confident that σ2 lies within this interval.
We are 95% confident that σ2 lies below this interval.
We are 95% confident that σ2 lies outside this interval
.We are 95% confident that σ2 lies above this interval.
(a)
The level of significance is
Hypotheses are:
(b)
Given information:
The chi-square statistic for the sample:
The degrees of freedom is:
df=n-1=23
We assume a normal population distribution.
(c)
The p-value using excel function "=CHIDIST(26.70,23)" is .02689.
Correct option:
P-value > 0.100
(d)
Since p-value is greater than 0.05 so we fail to reject the null hypothesis.
Since the P-value > α, we fail to reject the null hypothesis.
(e)
At the 5% level of significance, there is insufficient evidence to conclude conclude that the variance is greater in the new section.
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(f)
For 95% confidence interval value critical value of chi square statistics will be
The confidence interval for the population variance is
lower limit= 29.66
upper limit= 96.61
We are 95% confident that σ2 lies within this interval.