Question

In: Statistics and Probability

A transect is an archaeological study area that is 1/5 mile wide and 1 mile long....

A transect is an archaeological study area that is 1/5 mile wide and 1 mile long. A site in a transect is the location of a significant archaeological find. Let x represent the number of sites per transect. In a section of Chaco Canyon, a large number of transects showed that x has a population variance σ2 = 42.3. In a different section of Chaco Canyon, a random sample of 26 transects gave a sample variance s2 = 51.1 for the number of sites per transect. Use a 5% level of significance to test the claim that the variance in the new section is greater than 42.3. Find a 95% confidence interval for the population variance.

(a) What is the level of significance?
________________

State the null and alternate hypotheses.

a. Ho: σ2 = 42.3; H1: σ2 ≠ 42.3

b. Ho: σ2 = 42.3; H1: σ2 > 42.3    

c. Ho: σ2 > 42.3; H1: σ2 = 42.3

d. Ho: σ2 = 42.3; H1: σ2 < 42.3


(b) Find the value of the chi-square statistic for the sample. (Round your answer to two decimal places.)
__________________

What are the degrees of freedom?
________________

What assumptions are you making about the original distribution?

a. We assume a binomial population distribution.

b. We assume a exponential population distribution.    

c. We assume a normal population distribution.

d. We assume a uniform population distribution.


(c) Find or estimate the P-value of the sample test statistic.

P-value > 0.100

0.050 < P-value < 0.100    

0.025 < P-value < 0.050

0.010 < P-value < 0.025

0.005 < P-value < 0.010

P-value < 0.005


(d) Based on your answers in parts (a) to (c), will you reject or fail to reject the null hypothesis?

a. Since the P-value > α, we fail to reject the null hypothesis.

b. Since the P-value > α, we reject the null hypothesis.    

c. Since the P-value ≤ α, we reject the null hypothesis.

d. Since the P-value ≤ α, we fail to reject the null hypothesis.


(e) Interpret your conclusion in the context of the application.

a. At the 5% level of significance, there is insufficient evidence to conclude conclude that the variance is greater in the new section.

b. At the 5% level of significance, there is sufficient evidence to conclude conclude that the variance is greater in the new section.    


(f) Find the requested confidence interval for the population variance. (Round your answers to two decimal places.)

lower limit
upper limit    


Interpret the results in the context of the application.

a. We are 95% confident that σ2 lies below this interval.

b. We are 95% confident that σ2 lies above this interval.    

c. We are 95% confident that σ2 lies outside this interval.

d. We are 95% confident that σ2 lies within this interval.

Solutions

Expert Solution

Part a)

​​​​​​

b. Ho: σ2 = 42.3; H1: σ2 > 42.3   


n = 26


Test Statistic :-



Test Criteria :-
Reject null hypothesis if

= 30.2009 < 37.652 , hence we fail to reject the null hypothesis
Conclusion :- We Fail to Reject H0


Decision based on P value
P value = P ( \chi ^2 > 30.2009 )
P value = 0.2169
Reject null hypothesis if P value <
Since P value = 0.2169 > 0.05, hence we fail to reject the null hypothesis
Conclusion :- We Fail to Reject H0


the degrees of freedom?

26 - 1 = 25

P-value > 0.100

a. Since the P-value > α, we fail to reject the null hypothesis.

a. At the 5% level of significance, there is insufficient evidence to conclude conclude that the variance is greater in the new section.

part f)





Lower Limit =
Upper Limit =
95% Confidence interval is ( 31.43 , 97.37 )
( 31.43 < < 97.37 )

d. We are 95% confident that σ2 lies within this interval.


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