35.12 mL of 0.263 M zinc bromide solution needs to react how many
milliliters of with...
35.12 mL of 0.263 M zinc bromide solution needs to react how many
milliliters of with 0.258 M cesium hydroxide solution?
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How many milliliters of a 0.204 M HI solution are needed to
reduce 24.5 mL of a 0.371 M KMnO4 solution according to the
following equation: 10HI + 2KMnO4 + 3H2SO4 → 5I2 + 2MnSO4 + K2SO4 +
8H2O
How many milliliters of 1.27 M KOH should be added to
100. mL of solution containing 10.0 g of histidine hydrochloride
(His·HCl, FM 191.62) to get a pH of 9.30?
How many milliliters of 0.120 M NaOH are required to
tritrate 50.0 mL of 0.0998 M hydrochloric acid to the equivale
point the Ka of hypochlorous acid is 3.0×10^-8. What is the pH
after the NaOH is added?
How many milliliters of a solution that is 10.25% HNO3 (w/w)
with a density of 1.2792g/mL should be diluted in order to make
5.00L of a .250M HNO3 solution?
a.) How many milliliters of 1.0 M benzoic acid need to be added
to 550 mL of a solution already containing 6.00 grams of sodium
benzoate, if you want the final pH to be 4.15? Ka for benzoic acid
= 6.28x10^-5. b.) If you add 6.00 grams of sodium benzoate to 14.55
grams of benzoic acid, what is the pH of this solution? Is this a
buffer, why or why not? c.) How many grams of potassium nitrite
need to...
Part A: How many milliliters of 0.120 M NaOH are required to
titrate 50.0 mL of 0.0998 M butanoic acid to the equivalence point?
The Ka of butanoic acid is 1.5 x 10^-5.
Part B: What is the pH at the equivalence point?
(a) How many milliliters of 0.145 M HCl are needed to
neutralize completely 25.0 mL of 0.101 M
Ba(OH)2 solution?
ml
(b) How many milliliters of 2.50 M
H2SO4 are needed to neutralize 50.0 g of
NaOH?
mL
(c) If 56.8 mL of BaCl2 solution is needed to
precipitate all the sulfate in a 554 mg sample of
Na2SO4 (forming BaSO4), what is
the molarity of the solution?
M
(d) If 27.5 mL of 0.375 M HCl solution is needed...
a) How many milliliters of 0.0440 M H3PO4
could be completely neutralized by 33.8 mL of 0.175 M KOH? The
balanced equation for the reaction is
H3PO4(aq) + 3KOH(aq) →
K3PO4(aq) + 3H2O
b)How many milliliters of 0.241 M NaOH contain enough NaOH to
react with the H2SO4 in 24.2 mL of 0.175 M
H2SO4 according to the following
equation?
2NaOH(aq) + H2SO4(aq) →
Na2SO4(aq) + 2H2O
c) Suppose 24.9 mL of 0.162 M AgNO3 solution was
needed to react...