In: Chemistry
What mass of ammonium chloride should be added to 2.60 L of a 0.145 M NH3 in order to obtain a buffer with a pH of 9.45?
The pH of buffer is calculated using Hendersen Hassalbalch's equation. For basic buffer the equaiton is
pOH = pKb + log [salt] / [base]
Or
pH = pKa + log [base] / [salt]
Moles of base = Molarity X volume = 0.145 X 2.60 = 0.377 moles
pKa = 14 - pKb
Kb = 1.8 X 10−5 therefire pKb = -logKb = 4.745
pKa = 14- 4.745 = 9.255
pH = 9.45
pH = 9.45 = 9.255 + log [0.377 / [salt]
0.195 = log [0.377 / [salt]
Taking antilog
1.57 = 0.377 / [ salt]
[salt] = moles of salt = 0.2401
mass of salt (NH4Cl) = moles X molecular weight of NH4Cl
Molecular weight of NH4Cl = 53.5 g / mole
Mass of salt (NH4Cl0 = 0.2401 X 53.5= 12.85 grams