Question

In: Chemistry

In Europe, gasoline efficiency is measured in km/L. If your car's gas mileage is 22.0 mi/gal...

In Europe, gasoline efficiency is measured in km/L. If your car's gas mileage is 22.0 mi/gal , how many liters of gasoline would you need to buy to complete a 142-km trip in Europe? Use the following conversions: 1km=0.6214mi and 1gal=3.78L.

While in Europe, if you drive 107 km per day, how much money would you spend on gas in one week if gas costs 1.10 euros per liter and your car's gas mileage is 28.0 mi/gal ? Assume that 1euro=1.26dollars.

A sprinter set a high school record in track and field, running 200.0 m in 20.8 s . What is the average speed of the sprinter in kilometers per hour?

A specific brand of gourmet chocolate candy contains 7.00 g of dietary fat in each 22.7-g piece. How many kilograms of dietary fat are in a box containing 4.00 lb of candy?

Solutions

Expert Solution

1km=0.6214mi

or

0.6214mi = 1km

Therefore

22.0 mi = 1km x 22.0 mi / 0.6214 mi = 35.4 km

1gal=3.78L.

The car's gas mileage is 22.0 mi/gal = 35.4 km/3.78L.

The number of liters of gasoline needed to cover 35.4 km = 3.78L

The number of liters of gasoline needed to cover 142 km = 3.78L x 142 km / 35.4 km = 15.16 L

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0.6214mi = 1km

Therefore

28.0 mi = 1km x 28.0 mi / 0.6214 mi = 45.06 km

1gal=3.78L.

The car's gas mileage is 28.0 mi/gal = 45.06 km/3.78L.

The number of liters of gasoline needed to cover 45.06 km = 3.78L

The number of liters of gasoline needed to cover 107 km = 3.78L x 107 km / 45.06 km = 8.97 L

The number of liters of gasoline needed for 1 day = 8.97 L

The number of liters of gasoline needed for 7 days (1week) = 7x 8.97 L = 62.79 L

Cost of 1 L of gasoline = 1.10 euros

Therefore

Cost of 62.79 L of gasoline = 62.79 x1.10 euros = 69.07 euros

1 Euro = 1.26 dollars.

Therefore , 69.09 euros = 69.07 x 1.26 dollars.= 87.03 dollars

The money that would you spend on gas in one week = 87.03 dollars

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200.0 m = 0.200 km

20.8 s = [20.8 / (60x60) ] hour

200.0 m in 20.8 s = 0.200 km in [20.8 / (60x60)] hour

Average speed in = Distance in km/ Time in hour = [(0.200 x60x60 ) / 20.8] km/hour = 34.6 km/hour

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1 lb = 453.6 g

or

453.6 g = 1lb

Therefore

22.7 g = 1lb x 22.7 g / 453.6 g = 0.05 lb

7.00 g of dietary fat is present in each 22.7-g piece. or 0.05 lb piece

0.05 lb piece contains 7.00 g of dietary fat

Therefore

4.00 lb of candy will contain 7.00 g x 4.00 lb / 0.05 lb = 560 g of dietary fat = 0.560 kg of dietary fat

The number of kilograms of dietary fat are in a box containing 4.00 lb of candy = 0.560 kg

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queen_honey_blossom answered 1 year ago
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