A 130.0 mL sample of 0.070 M Ca 2 + is titrated with 0.070 M EDTA...

A 130.0 mL sample of 0.070 M Ca 2 + is titrated with 0.070 M EDTA at pH 9.00. The value of log K f for the Ca 2 + − EDTA complex is 10.65 and the fraction of free EDTA in the Y 4 − form, α Y 4 − , is 0.041 at pH 9.00. What is K ′ f , the conditional formation constant, for Ca 2 + at pH 9.00?

What is the equivalence point volume, Ve, in milliliters?

Calculate the concentration of Ca2+ at V=(1/2)Ve.

Calculate the concentration of Ca2+ at V=Ve.

Calculate the concentration of Ca2+ at V=1.1Ve.

Expert Solution

queen_honey_blossom answered 2 years ago

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A 130.0 mL sample of 0.070 M Ca 2 + is titrated with 0.070 M EDTA...

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