Question

In: Physics

An unpolarized beam of light is incident on a pair of polarizing filters. The first filter...

An unpolarized beam of light is incident on a pair of polarizing filters. The first filter set to polarize in the vertical direction and the second filter is set to polarize 38° from vertical. What is the intensity of the light beam after the second filter relative to the original beam?

Solutions

Expert Solution

To solve this problem you have to know about Polarizer and Malus's Law

Step 1.

Definition: Is an optical filter that passes light of a specific polarization and blocks waves of other polarizations.It can convert a beam of light of undefined or mixed polarization into a beam with well-defined polarization, polarized light.

Malus's Law: which is named after Étienne-Louis Malus, says that when a perfect polarizer is placed in a polarized beam of light, the intensity, I, of the light that passes through is given by   

where I0 is the initial intensity, and θi is the angle between the light's initial polarization direction and the axis of the polarizer. A beam of unpolarized light can be thought of as containing a uniform mixture of linear polarizations at all possible angles. Since the average value of is 1/2, the transmission coefficient becomes

  

Step 2.

ANSWERS:

How you can read in the above definition the intensity during the first polarizing filter is the following:

  

The intensity for the second polarizing filter is:

If you have any question pleaselet me know in the comments


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