In: Finance
Sadik Industries must install $1 million of new machinery in its Texas plant. It can obtain a 6-year bank loan for 100% of the cost at a 14% interest rate with equal payments at the end of each year. Sadik's tax rate is 34%. The equipment falls in the MACRS 3-year class. Alternatively, a Texas investment banking firm that represents a group of investors can arrange a guideline lease calling for payments of $320,000 at the end of each year for 3 years. Under the proposed lease terms, the Sadik must pay for insurance, property taxes, and maintenance. Sadik must use the equipment if it is to continue in business, so it will almost certainly want to acquire the property at the end of the lease. If it does, then under the lease terms it can purchase the machinery at its fair market value at Year 3. The best estimate of this market value is $200,000, but it could be much higher or lower under certain circumstances. If purchased at Year 3, the used equipment would fall into the MACRS 3-year class. Sadik would actually be able to make the purchase on the last day of the year (i.e. slightly before year 3), so Sadik would get to take the first depreciation expense at Year 3(the remaining depreciation expenses would be from Year 4 through Year 6). On the time line, Sadik would show the cost of purchasing the used equipment at Year 3 and its depreciation expenses starting at Year 3. To assist management in making the proper lease-versus-buy decision, you are asked to answer the following questions: a. What is the net advantage of leasing? Should Sadik take the lease? b. Consider the $200,000 estimate residual value. How high could the residual value get before the net advantage of leasing falls to zero?
a) | NAL OF LEASING: | |||||||
1) | NPV OF BUYING: | |||||||
Annual installments of the loan = 1000000*0.14*1.14^6/(1.14^6-1) = | 257157 | |||||||
Interest rate for discounting = 14*(1-34%) = | 9.24% | |||||||
0 | 1 | 2 | 3 | 4 | 5 | 6 | ||
Beginning balance of loan | 1000000 | 882843 | 749284 | 597027 | 423454 | 225580 | ||
Interest at 14% | 140000 | 123598 | 104900 | 83584 | 59283 | 31581 | ||
Total | 1140000 | 1006441 | 854184 | 680611 | 482737 | 257161 | ||
Installment | 257157 | 257157 | 257157 | 257157 | 257157 | 257161 | ||
Ending balance | 882843 | 749284 | 597027 | 423454 | 225580 | 0 | ||
Depreciation under MACRS | 333300 | 444500 | 148100 | 74100 | ||||
Cash flows of buying: | ||||||||
Principal repayment | -117157 | -133559 | -152257 | -173573 | -197874 | -225580 | ||
After tax interest [Interest * (1-34%)] | -92400 | -81575 | -69234 | -55165 | -39127 | -20844 | ||
Tax shield on depreciation | 113322 | 151130 | 50354 | 25194 | 0 | 0 | ||
After tax cash flows from buying | -96235 | -64004 | -171137 | -203545 | -237001 | -246423 | ||
PVIF at 9.24% [PVIF = 1/1.0924^n] | 0.91542 | 0.83799 | 0.76711 | 0.70222 | 0.64282 | 0.58845 | ||
PV at 9.24% | -88095 | -53634 | -131280 | -142933 | -152349 | -145008 | ||
NPV of buying | -713300 | |||||||
2) | NPV OF LEASING: | |||||||
After tax lease payments = 320000*(1-34%) = | -211200 | -211200 | -211200 | 0 | 0 | 0 | ||
Purchase of the leased asset | -200000 | |||||||
Depreciation tax shield on the leased asset acquired | 22664 | 30226 | 10071 | 5039 | ||||
After tax cash flows from leasing | -211200 | -211200 | -388536 | 30226 | 10071 | 5039 | ||
PVIF at 9.24% [PVIF = 1/1.0924^n] | 0.91542 | 0.83799 | 0.76711 | 0.70222 | 0.64282 | 0.58845 | ||
PV at 9.24% | -193336 | -176983 | -298048 | 21225 | 6474 | 2965 | ||
NPV of leasing | -637702 | |||||||
3) | NAL OF LEASING = -637702-(-713300) = | 75598 | ||||||
DECISION: | ||||||||
As the NAL is positive, Sadiq should take the lease. | ||||||||
b) | If the NAL is to be zero, the residual value at t3 should be increased such that the PV of the increase in price-the PV of tax shields on the addl depreciation | |||||||
should be 0. | ||||||||
If x is the increase in residual value: | ||||||||
PV of increase in residual value = x*0.76711 | ||||||||
The PV of depreciation tax shield will be x*0.34*(0.3333*.76711+0.4445*0.70222+0.1481*0.64282+0.0741*0.58845) = x*0.24025 | ||||||||
So 75598 = x*(0.76711-0.24025) | ||||||||
x = 75598/(0.76711-0.24025) = | 143488 | |||||||
The increase in price should be $143488. | ||||||||
That is the residual value should be 200000+143488 = | 343488 | |||||||
for NAL to be 0. |