In: Chemistry
Ignoring activities, determine the molar solubility (S) of Zn(CN)2 in a solution with a pH = 1.34. Ksp (Zn(CN)2) = 3.0 × 10-16; Ka (HCN) = 6.2 × 10-10.
pH = 1.34
[H+] = 10^-pH = 10^-1.34 =0.0457 M
[H+] = [CN-] = 0.0457 M
Zn (CN)2 ---------------------------> Zn+2 + 2CN-
S 2S
S 0.0457
Ksp = [Zn+2] x (0.0457)^2
3.0x 10^-16 = S x (0.0457)^2
S = 1.44 x 10^-13 M
molar solubility = 1.44 x 10^-13 M