In: Physics
slits s1 and s2 are illuminated by a monochromatic source of light. The two slits act as source of light and they are coherent sources.
Light waves from s1 and s2 meet at a point P. on a screen at a distance D
Path difference between the two rays difference by a distance dSin
The two wave meeting at P will constructively interfere and produce a bright spot if the path difference between the two is an integral multiple of
dSin = n ( n = 0, +/-1, +/-2 , .... )
for n=0 , the path difference is 0 and there will be bright spot , where P is on a line through the center of both slits.
for small angles w can approximate Sin = Tan = y/D
for y = nD/d , we have bright fringes on the screen
b)
1 = 589.522 nm ; 2 = 588.995 nm
grating has 600 lines /mm
d = 1/600 mm = 1.67 E-6 m
y1 = D/d = D 589.522E-9 / 1.67E-6 = 0.3530 D
y2 = D* 588.995E-9/ 1.67E-6 = 0.3527 D
we want y1 -y2 = 0.0003D = 10*1.7 = 17 nm
D = 17E-9 / 0.0003 = 5.667 E-5 m
The distance is too small for the camera to be positioned correctly.
c) the question is not connected.