In: Statistics and Probability
The average time taken for your Internet service provider to remotely resolve a trouble ticket has a Normal distribution with a mean of 4.3 hours and a standard deviation of 3.1 hours. One day your service provider selects 100 trouble ticket. What is a probability that an average time to resolved these 100 tickets will be less than 4 hrs?
Solution :
Given that,
mean = = 4.3
standard deviation = = 3.1
n = 100
= 4.3
= / n = 3.1 / 100=0.31
P( < 4) = P[( - ) / < (4-4.3) /0.31 ]
= P(z <-0.97 )
Using z table
= 0.1660
probability= 0.1660